When the sides of a square are increased by 4, area become 256. Find t

1.	When the sides of a square are increased by 4, area become 256. Find the length of the first square.
Answer» Let x be the side of square (x + 4)²= 256 x² + 8 x - 240 = 0 \(x=\frac{-8\,\pm\, \sqrt{64\,+\,960}}{2}=\frac{-8 \,\pm\,32}{2}\) = 12, -20 x will not -20 The side of the first square = 12 cm

When the sides of a square are increased by 4, area become 256. Find the length of the first square.

Answer»

Let x be the side of square

(x + 4)²= 256

x² + 8 x - 240 = 0

\(x=\frac{-8\,\pm\, \sqrt{64\,+\,960}}{2}=\frac{-8 \,\pm\,32}{2}\) = 12, -20

x will not -20

The side of the first square = 12 cm

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When the sides of a square are increased by 4, area become 256. Find the length of the first square.

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