1.

When the ratio of the minimum velocity to the maximum velocity is 1/√2 , the angle of projection of projectile is​

Answer»

At the time t=0, the projectile has the MAXIMUM speed vertically.  At the maximum height the projectile has minimum θ vertical speed.

ϕ= ANGLE of projection

So minimum speed =ucosϕ

Maximum speed =u

Now you can solve it so angle of projection is 45 degrees.

Hope you have a NICE day, good LUCK :)


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