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When the number N = \(0.735\overline{45}\) is written as a fraction in its lowest terms, the denominator exceeds the numerator by(a) 199 (b) 299 (c) 109 (d) 219 |
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Answer» (b) 299 N = \(0.735\overline{45}\) = \(\frac{73545 -735}{99000}=\frac{72810}{99000}=\frac{809}{1100}\) ∴ Required difference = 1100 – 809 = 299. |
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