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| 1. |
When the current in the portion of the circuit shown in the figure is `2A` and increasing at the rate of `1A//s`,the measured potential difference `V_(a)-V_(b)=8V`.However when the current is `2A` and decreasing at the rate of `1A//s`, the measured potential difference `V_(a)-V_(b)=4V`.The values of `R` and `L` are: A. 3 ohm and 2 Henry respectivelyB. 2 ohm and 3 Henry respectivelyC. 10 ohm and 6 Henry respectivelyD. 6 ohm and 1 Henry respectively |
| Answer» Correct Answer - A | |