Saved Bookmarks
| 1. |
When the brakes are applied to moving car, the car travels a distance ‘s’ ft. in ‘t’ see given by s = 8t – 6t2 when does the car stop? |
|
Answer» Given s = 8t – 6t2 v = \(\frac{ds}{dt}\)= 8 – 12t car stops when v = 0 ∴ 8 – 12t = 0 ⇒ t = \(\frac{8}{12}\)= \(\frac{2}{3}\) sec. |
|