1.

When redox reaction stops by achieving equilibrium then what will be true for E_(cell)^(Theta) of following reaction ? Al_((S)) +3Cu_((aq))^(2+) to 2Al_((aq))^(3+)+3Cu_((S))

Answer»

`E_(cell)^(THETA)=(0.059)/(2)"log"([AL^(3+)]^(2))/([CU^(2+)]^(2))`
`E_(cell)^(Theta)=(0.059)/(6)"log"([Al^(3+)])/([Cu^(2+)])`
`E_(cell)^(Theta)=(0.059)/(6)"log"([Al^(3+)]^(2))/([Cu^(2+)]^(3))`
`E_(cell)^(Theta)=0.059"log"([Al^(3+)]^(2))/([Cu^(2+)]^(3+))`

Solution :`E_(cell)^(Theta)=(0.059)/(6)"log"([Al^(3+)]^(2))/([Cu^(2+)]^(3))`


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