When p(x)=x3+ax2+2x+a is divided by (x+a), the remainder is: (a) 0 (b) a (c) -a (d) 2a

When p(x)=x3+ax2+2x+a is divided by (x+a), the remainder is: (a) 0 (b)

1.	When p(x)=x3+ax2+2x+a is divided by (x+a), the remainder is: (a) 0 (b) a (c) -a (d) 2a
Answer» When $p (x) = x^{3} + a x^{2} + 2 x + a$ is divided by (x+a), the remainder is: (a) 0 (b) a (c) -a (d) 2a