When p(x) x^4+2x^3-3x+2-1 is divided by (x-2) what will the remainder?

1.	When p(x) x^4+2x^3-3x+2-1 is divided by (x-2) what will the remainder???
Answer» Answer: Remainder = 21 Step-by-step explanation: I guess you have some mistake in the question. Here is the corrected statement We have been given the the EXPRESSION:- $x^{4} + 2x^{3} - 3x^{2} + x - 1$ We are REQUIRED to FIND the remainder when it is DIVIDED by:- $x - 2$ Let $x - 2 = 0$ $x = 2$ Substitute the value of 'x' in the expression:- $p(2) = (2)^{4} + 2(2)^{3} - 3(2)^{2} + (2) - 1$ $p(2) = 16 + 2(8) - 3(4) + (2) - 1$ $p(2) = 16 + 16 - 12 + 2 - 1$ $p(2) = 21$ $x^{4} + 2x^{3} - 3x^{2} + x - 1$ $x - 2$ Therefore, when is divided by then the remainder is 21 !