1.

When load is applied to a wire the extension is 3 mm, the extension in the wire of same material, length but half the radius by the same load is :

Answer»

0.75 mm
6 mm
1.5 mm
12.0 mm

Solution :`Deltal=(FL)/(Ay)rArr1lprop1/A`
or `Deltalprop1/(R^(2))`
`therefore(Deltal_(2))/(Deltal_(1))=(r_(1)^(2))/(r_(2)^(2))=(2/1)^(2)=4`
`rArrDeltal_(2)=4Deltal_(1)=4xx3=12mm`
So, the correct CHOICE is (d).


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