when laxmi applied a force of 50 newton on an object it undergoes a di

1.	when laxmi applied a force of 50 newton on an object it undergoes a displacemnt of 2m when vinitha aplien the same forceon it it displaced 3m if so which one did more work
Answer» Given:- Force ,F = 50 N Displacement ,s = 2 m Displacement ,s' = 3m To Find:- Which one work more ,W Solution:- As we know that Work DONE is defined when force acting on the object produce some displacement . • W = Fs Where, W is the Work Done F is the Force s is the displacement Work done by Laxmi !! substitute the value we get → W = 50 × 2 → W = 100 J -------------(1) THEREFORE,work done by laxmi is 100 Joules. And, Work done by vinitha !! Substitute the value we get → W' = 50×3 → W' = 150 J ----------------(2) Therefore,work done by vinitha is 150 Joules. From Equation 1 & 2 we observe that work done by vinitha is more .

when laxmi applied a force of 50 newton on an object it undergoes a displacemnt of 2m when vinitha aplien the same forceon it it displaced 3m if so which one did more work

Answer»

Given:-

Force ,F = 50 N

Displacement ,s = 2 m

Displacement ,s' = 3m

To Find:-

Which one work more ,W

Solution:-

As we know that Work DONE is defined when force acting on the object produce some displacement .

• W = Fs

Where,

W is the Work Done

F is the Force

s is the displacement

Work done by Laxmi !!

substitute the value we get

→ W = 50 × 2

→ W = 100 J -------------(1)

THEREFORE,work done by laxmi is 100 Joules.

And,

Work done by vinitha !!

Substitute the value we get

→ W' = 50×3

→ W' = 150 J ----------------(2)

Therefore,work done by vinitha is 150 Joules.

From Equation 1 & 2 we observe that

work done by vinitha is more .

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