Related InterviewSolutions

• In the given circuit, the potential difference between A and B is
• The circuit as shown in the figure is equivalent to A. AND gateB. NOT gateC. OR gateD. NAND gate
• Two radioactive materials `X_(1)` and `X_(2)` have decay constant `11 lambda` and `lambda` respectively. If initially they have same number of nuclei, then ratio of number of nuclei of `X_(1)` to `X_(2)` will be `(1)/(e^(2))` after a timeA. `(1)/(10 lambda)`B. `(1)/(11 lambda)`C. `(11)/(10 lambda)`D. `(1)/(9 lambda)`
• Which one of the following combinations of radioactive decay results in the formation of an isotope of original nucleus ?A. One alpha, four betaB. One alpha, two betaC. One alpha, one betaD. Four alpha, one beta
• In common emitter amplifier, the current gain is 62. The collector resistance and input resistance are `5 k Omega` an `500 Omega` respectively. If the input voltage is 0.01V, the output voltage isA. `0.62 V`B. `6.2 V`C. `62V`D. `620 V`
• The critical angle of a certain medium is `sin ^(-1)((3)/(5))`. The polarizing angle of the medium is :A. `sin^(-1)((4)/(5))`B. `tan^(-1)((5)/(3))`C. `tan^(-1)((3)/(4))`D. `tan^(-1)((4)/(3))`
• In a sample of radioactive material, what percentage of the initial number of active nuclei will decay during one mean life ?A. `63%`B. `69.3%`C. `37%`D. `50%`
• Critical angle of glass is `theta_(1)` and that of water is `theta_(2)`. The critical angle for water and glass surface would be `(mu_(g)=3//2, mu_(w)=4//3)`A. between `theta_(1)` and `theta_(2)`B. greater than `theta_(2)`C. less than `theta_(1)`D. less than `theta_(2)`
• In an AC circuit, a resistance of `Rohm` is connected is series with an inductance `L`. If phase angle between volage and current be `45^(@)`, the value of inductive reactance will beA. `(R)/(4)`B. `(R)/(2)`C. RD. cannot be found with given data
• A particle of mass m and charfe Q is placed in an electric filed W which varies with time t as E = `E_(0) sin omegat`. It will undergo simple harmonic motion of amplitude.A. `(QE_(0)^(2))/(m omega^(2))`B. `(QE_(0))/(m omega^(2))`C. `sqrt((QE_(0))/(m omega^(2)))`D. `(QE_(0))/(m omega)`