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When `H_(2)O_(2)` react with `N_(2)H_(4)` then `H_(2)O_(2)` oxidised `N_(2)H_(4)`. The no. of mole of `H_(2)O_(2)` required to oxidised 64gm `N_(2)H_(4)`. |
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Answer» Correct Answer - 4 `2H_(2)O_(2)rarr2H_(2)O+2[O]` `N_(2)H_(4)+2[O]rarr N_(2)uarr +2H_(2)O` `ul(bar(N_(2)H_(4)+2H_(2)O rarrN_(2)uarr+4H_(2)O))` |
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