1.

When Cl_(2) gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from

Answer»

zero to +1 and zero to +5
zero to -1 and zero to +5
zero to -1 and zero to +3
zero to +1 and zero to -3

Solution :`3overset(0)(Cl_(2)) + 6 NAOH (conc.) overset(Delta)rarr 5 Naoverset(-1)(CL) + Naoverset(+5)(ClO_(3))+ 3H_(2)O`
Here, O.N. of Cl changes from 0 in `Cl_(2)` to -1 in NaCl and from 0 in `Cl_(2)` to +5 in `NaClO_(3)`.


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