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When brakes are applied to a moving car, the car travels a distance ‘s’ feet in ‘t’ secs is given by s = 20t – 40t2. When does the car stop? |
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Answer» Given s = 20t – 40t2 v = \(\frac{ds}{dt}\) = 20 – 80t The car stops when the velocity = 0 ⇒ 20 – 80t = 0 ⇒ t = \(\frac{1}{4}\)sec |
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