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When body of mass m is suspended from a spiral spring and spring gets stretched through a distance 20 cm if it is stretched below 20 cm and leave then what is period of oscillation? |
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Answer» Solution :`T= 2pi sqrt((l)/(G))` `= 2pi sqrt((20)/(980))= 2pi xx sqrt((1)/(49))` `THEREFORE T = (2xx22)/(7) xx (1)/(7) = (44)/(49)s`. |
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