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When an object is placed at a distance of 30 cm from a concave mirror of radius curvature 30 cm. What is the magnification of the image and why?

Answer» MAGNIFICATION of IMAGE = - 1Explanation:u = - 30 cmR = - 30 cmf = R/2 = - 30/2 = - 15 cmMirror formulae: 1 /v + 1 /u = 1 /F1 /v = - 1 /15 + 1 /30       = - 1 /30v = - 30 cmMagnification of image: m = - v /um = 30 /- 30    = - 1The image is real, INVERTED and is same size as that of the object.


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