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when an object is placed at 5 metres in front of a convex mirror of radius of curvature 6 metres then calculate the image distance and also write the properties of image ? |
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Answer» Answer: hope you like this ONE Step-by-step explanation: Given; u =-5 r=6 therefore f =3 1/v= 1/f -1/u v= uf/u-f = -15/-8 =1.875 therefore the images VIRTUAL end erect please mark it as brainliest one |
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