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When ammonia is heated with cupric oxide, a molecule of ammonia willA. gain 3 electronsB. lose 3 electronsC. gain 2 electronsD. lose 2 electrons |
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Answer» Correct Answer - B `NH_3` reduces cupric oxide CuO to forming `N_2`. `2NH_3 +3CuOto 3Cu+3H_2O+N_2uarr` `2NH_3` molecules lose `6e^(-)`. `therefore ` One `NH_3` will lose `3e^(-)`. |
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