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When a wire is stretched and its radius becomes `r//2` then its resistance will beA. 16 RB. 4 RC. 2 RD. `R//2`

Answer» Correct Answer - A
`(R_(2))/(R_(1))=((r_(1))/(r_(2)))^(4)`
`R_(2)=(((r_(1))/(r_(1)))/(2))^(4)xxR_(1)=16.R_(1)=16R`


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