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When a screw gauge is completely closed, zero of circular scale is `7` divisions above the reference line of graduation. If `LC` of screw gauge is `10^(-3) cm`, the zero error isA. `-7xx10^(-3)cm`B. `+7xx10^(-3)cm`C. `-0.007mm`D. `+0.007mm` |
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Answer» Correct Answer - A As zero of ciruclar scale is above the reference line of graduation, zero correction is positive and zero error is negative. `Zero error=-7xx10^(-3)cm` |
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