1.

When a particle is moving in vertical circle

Answer»

Solution :(i) A body of mass (m) attached to one end of a massless and inextensible stringexecutes circular motion in a VERTICAL plane with the other end of the string fixed. The length of the string becomes the radius `vecr` of the circular PATH.
(ii) The motion of the body by taking the free body diagram (FBD) at a position where the position vector `vecr` makes an angle `theta` with the vertically downward direction and the instantaneous velocityis as shown in Figure.
There are two forces acting on the mass.
1. Gravitationalforce which acts downward
2. TENSION ALONG the string.

Applying Newton's second law on the mass,
In the tangential direction,
`mg sin theta=ma_(t)`
` mg sin theta= -m((dv)/(dt))`.
where, `a_(t)= -((dv)/(dt))` is tangential retardation
In the radial direction,
`T-mg cos theta=m a_(r), T-mg cos theta=(mv^(2))/(r)`
where, `a_(r)=(v^(2))/(r)` is the centripetal acceleration.


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