1.

When a large bubble rises from the bottom of a lake to the surface , its radius doubles .The atmospheric pressure is equal to that of a columnof water of height H. What is the depth of the lake ?

Answer»

7H
8H
H
2H

Solution :If `P_(1)` is the internal PRESSURE of bubble at the BOTTOM then ,
`P_(1)xx(4)/(3)piR_(1)^(3)=P_(2)xx(4)/(3)piR_(2)^(3)`
where `P_(2)` is the EXCESS pressure inside the bubble at the surface and `R_(2)=2R_(1)`
`P_(1)xx(4)/(3)piR_(1)^(3)=P_(2)xx(4)/(3)pixx8R_(1)^(3)`
`thereforeP_(1)=8P_(2)rArrP_(2)=(P_(1))/(8)`
Pressure at surface `=("pressure at bottom")/(8)`
`H=(H+h)/(8)`
where h= depth of lake
`8H=H+h`
`thereforeh=7H`


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