When a glass capillary tube is dipped in pure water, water rises to a height .h. in the tube. Capillary tube is pushed down till its height above the surface of water is h^(1)[h^(1)lth]. Find the relation between h and h^(1).

When a glass capillary tube is dipped in pure water, water rises to a

1.	When a glass capillary tube is dipped in pure water, water rises to a height .h. in the tube. Capillary tube is pushed down till its height above the surface of water is h^(1)[h^(1)lth]. Find the relation between h and h^(1).
Answer» Solution :`h=(2Scostheta)/(rrhog)rArrhpropcostheta` `h/h^(1)=(costheta_(1))/(costheta_(2))=(cos0^(@))/(costheta_(2))rArrcostheta_(2)=h^(1)/h` `theta_(2)=cos^(-1)(h^(1)/h)` In the SPECIAL CASE angle of contact will change even if PAIR of solid & liquid are not CHANGED.