When a force of 10.0 N is exerted on the handle of a door, the door can be just opened. If the handle is a distance of 50 cm from the hinges find the torque applied on the door.

When a force of 10.0 N is exerted on the handle of a door, the door ca

1.	When a force of 10.0 N is exerted on the handle of a door, the door can be just opened. If the handle is a distance of 50 cm from the hinges find the torque applied on the door.
Answer» Solution :`tau = R F SIN theta = 0.50 xx 10.0 sin 90^(@)=5Nm`