1.

When a driver of Shatabdi Express, running with velocity 108 km/hr, sights a goods train going ahead of him at a distance 50 m in the same direction on the same track, running with velocity 72 km/hr, he applies brakes. In order to avoid an accident, what should be the magnitude of the deceleration produced by the brakes?

Answer»

`5 ms ^(-2) `
`1 ms ^(-2)`
`3 ms ^(-2)`
None of these

Solution :`v _(1) = (108 xx 1000)/(3600) = 30m//s, v _(2) = (72 xx 1000)/(3600) = 20 m//s.`
Initial velocity of Shatabdi Express
`v _(0) = v _(12) = v _(1) -v _(2) `
`v _(0) = 30 - 20 = 10 ms ^(-1)`
Now `v ^(2) =v _(0) ^(2) + 2AD`
Putting `v =0, v _(0) =10 ms ^(-1), d=50 m,`
`0= 100 + 2 xx a xx 50`
`THEREFORE a xx 100 =- 100`
`therefore a =-1`
`therefore -a =1 ms ^(-2)`
`therefore` DECELERATION `=1 ms ^(-2)`


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