When a current of (5 +- 0.5)A flows through a wire, it develops a potential difference of (40 +- 1)V. The resistance of the wire is ......

When a current of (5 +- 0.5)A flows through a wire, it develops a pote

1.	When a current of (5 +- 0.5)A flows through a wire, it develops a potential difference of (40 +- 1)V. The resistance of the wire is ......
Answer» `(8+-1.5) Omega` `(8+-0.5)Omega` `(8+-1)Omega` `(8+-2)Omega` Solution :`R=(V)/(1)=(40)/(5)=8OMEGA` `:.(DeltaR)/(R)=(DeltaV)/(V)+(DeltaI)/(I)` `:. (DeltaR)/(8)=(1)/(40)+(0.5)/(5)=(1+4)/(40)=(5)/(40)` `:. DeltaR=(5)/(40)xx8=1Omega` `:.` Resistance of WIRE `=R+-DeltaR` `=(8+-1)Omega`