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When a car of mass 1200 kg is moving with a velocity of 15m/s on a rough horizontal surface?

Answer»

A car with a mass of 1,000 kg is moving with a velocity of 20 m/s. If on applying brakes, the car stops after coming to a distance of 50 m, what will be its retarding force?

The car stops after TRAVELING 50m. So, from the laws of MOTION,

V^2=U^2+2D(-a)

where V is the velocity at the end

U us its initial velocity

D is the distance traveled before coming to REST after applying retarding force

a us the acceleration but negative because retarding.

So

0=20^2–2*50*a

Or, 100a=400

So, a=4 ms^-2

Since the mass of the car is 1000 kg. So

F=m*a

=1000*4

=4000N

So the applied force is 4000 Newton's


this is just a example
I HOPE this will help you


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