When a bouler of mass 240kg is placed on a floating iceberg, it is found that the iceberg just sinks. What is the mass of iceberg? (Given R.D. of ice=0.90 and density of sea water=1.02).

When a bouler of mass 240kg is placed on a floating iceberg, it is fou

1.	When a bouler of mass 240kg is placed on a floating iceberg, it is found that the iceberg just sinks. What is the mass of iceberg? (Given R.D. of ice=0.90 and density of sea water=1.02).
Answer» Solution :MASS of bouler =240kg Let the mass of iceberg =M `rho_("ice")=90kgm^(-3)""rhg_(w)=1020kgm^(-3)` APPLYING (240+M)g= `vrho_(p_(w))g.` we get `240+M=(M)/(rho)S_(w) 240=M((rho_(w))/(rho)-1)` hence `M=(240)/((rho_(w))/(rho)-1) =(240)/((1020)/(900)-1)=(240 xx 45)/(rho)` M=1800kg