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When a block of mass 5kg is suspended by a long wire of length 1m, the length of wire becomes 2.001 energy stored in the stretched wire is (g = 10m/s2)(A) 25J(B) 0.25J(C) 0.025J(D) 0.0025J |
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Answer» please mark me as BRAINLIST Explanation:hope it helps you to UNDERSTAND Stay home,stay SAFE |
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