1.

When 9.65 Coulomb of electricity is passed through a solution of silver nitrate (Atomic weigth of Ag = 107.85g), the amount of silver deposited is ………………….. .

Answer»

`10.8 mg`
`5.4 mg `
`16.2 mg`
`21.2 mg`

SOLUTION :`W_(Ag) = (E_(Ag) xx Q)/(96500) = (108 xx 9.65)/(96500)`
`= 1.08 xx 10^(-2)g = 10.8 mg`.


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