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When .^(30)Si bombarded with a deutron. .^(31)Si is formed in its ground state with the emission of a proton. The energy released in this reaction from the following is E then find [E]:- |
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Answer» `Q=M_(d)+M_(Si^(30))-M_(si^(31))-M_(p)` .....(2) Given `M_(si^(30)+M_(d)=M_(p)^(31))+M_(N)+5.1` .....(3) `M_(Si)^(31)=M_(p^(31))+M_(e )+1.51` ......(4) Subtract (4) from (3) `M_(si^(30))+M_(d)-M_(si^(31))=M_(n)-M_(e )+3.59` .......(5) Further `M_(n)=M_(p)+M_(e )+OVERSET(-)v+0.78` .......(6) ADD (5) and (6) `M_(si^(30))+M_(d)-M_(si^(31))-M_(p)=Q=3.59+0.78=4.37MeV` |
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