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when 22.4 litres of h2 (g)is mixed with the 11.2 litres of Cl2(g),each at STP, the moles of HCL(g)formed is equal to |
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Answer» Answer: Cl2=0.5mole here the LIMITING REAGENT is cl2 so 1mole of cl2 gives 2moles of HCL then 0.5 MOLES cl2 gives how MANY moles of hcl 2×0.5÷1 =1mole |
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