Saved Bookmarks
| 1. |
When 12 litres of water were added with some quantity of pure watermelon juice then the ratio of juice to water become 5 : 4Quantity I: In the mixture, when 2 litres of pure watermelon juice are added then what will be the concentration of juice in the new mixture? Quantity II: Instead of 12 litres of water, if 5 litres of water were added and the quantity of pure watermelon juice remained the same then what would be the concentration of pure watermelon juice in the mixture?1. Quantity 1 > Quantity 22. Quantity 1 ≥ Quantity 23. Quantity 1 < Quantity 24. Quantity 1 ≤ Quantity 25. Quantity 1 = Quantity 2 |
|
Answer» Correct Answer - Option 3 : Quantity 1 < Quantity 2 Given: Ratio of juice to water = 5 : 4 Water = 12 L Calculations: Let the quantity of pure watermelon juice = 5x litres and quantity of water = 4x litres ⇒ 4x = 12 litres ⇒ x = 3 litres ⇒ the quantity of pure milk = 5x ⇒ 5 × 3 = 15 litres Quantity I: In the mixture, when 2 litres of pure watermelon juice are added then the quantity of pure juice = 15 + 2 = 17 litres ⇒ The quantity of mixture = 17 + 12 = 29 litres ⇒ The concentration of watermelon juice = (15 × 100) / 29 ⇒ The concentration of watermelon juice ≈ 51.7% ∴ concentration of watermelon juice ≈ 52% Quantity II: Instead of 12 litres of water, if 5 litres of water were added and the quantity of pure juice remained the same then the quantity of pure juice = 15 litres, the quantity of water = 5 litres ⇒ the quantity of mixture = 15 + 5 = 20 litres ⇒ required concentration = 15 × 100/20 ⇒ required concentration = 75% ∴ Quantity I < Quantity II |
|