When `100 V` DC is applied across a solenoid, a current of `1.0 A` flows in it. When `100 V` AC is applied across the same coil. The current drops to `0.5A`. If the frequency of the ac source is `50 Hz`, the impedance and inductance of the solenoid areA. `100Omega,5.05Omega`B. `210Omega,5.50H`C. `200Omega,5.55H`D. `200Omega,0.55H`

When `100 V` DC is applied across a solenoid, a current of `1.0 A` flo

1.	When `100 V` DC is applied across a solenoid, a current of `1.0 A` flows in it. When `100 V` AC is applied across the same coil. The current drops to `0.5A`. If the frequency of the ac source is `50 Hz`, the impedance and inductance of the solenoid areA. `100Omega,5.05Omega`B. `210Omega,5.50H`C. `200Omega,5.55H`D. `200Omega,0.55H`
Answer» Correct Answer - D `R=(V_(dc))/(I_(dc))` `=(100)/(1)=100Omega` `Z=(e_(rns))/(I_(rns))` `=(100)/(0.5)=200Omega` `therefore X_(L)=sqrt(Z^(2)-R^(2))=173Omega` `L=(X_(L))/(2pif)=0.55H`

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