1.

When 1 mole of CrCl3.6H2O is treated with excess of AgNO3, 3 moles of AgCl are obtained. The formula of the complex is (a) [CrCl3(H2O)3]3H2O (b) [CrCl3(H2O)4]Cl2.2H2O (c) [CrCl3(H2O)5]Cl2.H2O (d) [Cr(H2O)6]Cl3

Answer»

When 1 mole of CrCl3.6H2O is treated with excess of AgNO3, 3 moles of AgCl are obtained. The formula of the complex is
(a) [CrCl3(H2O)3]3H2O
(b) [CrCl3(H2O)4]Cl2.2H2O
(c) [CrCl3(H2O)5]Cl2.H2O
(d) [Cr(H2O)6]Cl3



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