1.

When 1 kg of ice at 0^@ C melts to water at 0^@ C, the resulting change in its entropy, taking latent heat of ice to be 80 "cal/".^@C is ____

Answer»

`273 "cal"/K`
`8xx104"cal"/K`
`80"cal"/K`
`293"cal"/K`

Solution :Change in ENTROPY `dS=(dQ)/T`
`THEREFORE DeltaS=(DeltaQ)/T=(mL_f)/273`
`therefore DeltaS=(1000xx80)/273`=293 cal/K


Discussion

No Comment Found