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When 0.2 mol CrCl3.6H2O is treated with excess of AgNO3, 0.4 mol of AgCl are obtained. The formula of the complex is |
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Answer» When 0.2 mol CrCl3.6H2O is treated with excess of AgNO3, 0.4 mol of AgCl are obtained. The formula of the complex is |
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