1.

When 0.2 mol CrCl3.6H2O is treated with excess of AgNO3, 0.4 mol of AgCl are obtained. The formula of the complex is

Answer»

When 0.2 mol CrCl3.6H2O is treated with excess of AgNO3, 0.4 mol of AgCl are obtained. The formula of the complex is




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