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What would the molecular of a gas have to be if the pressure of the gas is to fall one-half of its value in a vertical of a 1 metre ? (T = 25^(@)C). What type of molecules have molecular weight of this magnitude ? |
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Answer» Solution :We have, `2.303 log""(p)/(p_(0) = -(Mgh)/(RT)` p = p(suppose) `p_(0) = 2P` `g = 981 cm//s^(2)` h = 100 cm `R = 8.314 xx 10^(7) erg. K^(-1)"mole"^(-1)` `T = 25 + 273 = 298 K`. `therefore 2.303 log""(P)/(2P) = (M xx 981 xx 100)/(8.314 xx 10^(7) xx 298)` M = 17500 Molecules with such a high value of molecular weight must be those of a polymer. |
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