1.

What would be the final temperature of mixture of 50g of water at 20C temperature and 50g of water at 40C temperature?

Answer»

water at 20 ⁰ C and 50 gms of water at 40⁰ C are mixed.  Since the masses of the liquid at different temperatures are same, the answer is very EASY and simple :  average of 20⁰C and 40⁰C.  that is:  30⁰C.=====================final temperature of the mixture =      = [ m1 * T1 + m2 * T2 ] / (m1 + m2)     = [ 50 gms * 20⁰ C + 50 gms * 40⁰C ]  / (50+50)     = 3,000 / 100 = 30⁰C====================another way using specific heats :   let the final temperature be = T ⁰C   Amount of heat given out by the hot water = m * s * (40⁰C - T)           = 50 gms * s* (40 -T)   Amount of heat TAKEN in by the cold water = m * s * (T - 20⁰C)       = 50 gms * s * (T - 20 )   As the amounts are equal, because the heat is transferred from hotwater to the cold water without any loss of heat to any surroundings,           50 * s * (40 -T) = 50 gm * s  * (T-20)                  40 - T = T - 20             2 T = 60    => T = 30⁰C=============================



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