1.

What would be the change in tangential velocity of an electron, if it remains in same orbit and electronic charge is doubledHint:if v is proportional to square root of charge

Answer»

ANSWER:

(\sqrt{<klux>2</klux>}-1)v

Explanation:

1) We know that,

Columbic force which PROVIDES centripetal acceleration to the electron is proportional to charge q of moving particle. (Here electron )

And centripetal acceleration is proportional to square of its velocity.

2) Moving swiftly to equations, we get

F_c \propto q\\ \\=>v^2 \propto q \\ =>v \propto \sqrt{q}

3) If charge gets doubled,

Then,

We have, v_i = INITIAL tangential velocity

v_f = final tangential velocity

\frac{v_f}{v_i}=\frac{\sqrt{2q}}{\sqrt{q}}\\ \\=>v_f = \sqrt{2}v_i

CHANGE in tangential velocity,

\Delta v=v_f-v_i\\ \\ =(\sqrt{2}-1)v_i



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