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What will be the y intercept of the 5000 N force if its moment about A is 8000 N-m in Fig. |
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Answer» 5000 N force is shifted to a point B along its line of action (law of transmissibility) and it is resolved into its x and y components (Fx and Fy as shown in) Fx = 5000 cos θ = 5000 x 4/5 = 4000 N and Fy = 5000 sin θ = 5000 x 3/5 = 3000 N. By Varignon's theorem, moment of 5000 N force about A is equal to moment of its component forces about the same point. 8000 = 4000 × y + 3000 × 0 ∴ y = 2 m. |
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