What will be the work done when one mole of a gas expands isothermally

1.	What will be the work done when one mole of a gas expands isothermally from 15L to 50L against a constant pressure at 1atm at 25 C
Answer» ANSWER: The work done for the given process is -3546.55 J Explanation: To calculate the AMOUNT of work done for an isothermal process is given by the equation: $W=-P\Delta V=-P(V_2-V_1)$ W = amount of work done = ? P = pressure = 1 atm $V_1$ = initial volume = 15 L $V_2$ = FINAL volume = 50 L Putting values in above equation, we get: $W=-1atm\times (50-15)L=-35L.atm$ To convert this into joules, we use the conversion factor: $1L.atm=101.33J$ So, $-35L.atm=-35\times 101.3=-3546.55J$ The negative sign indicates the system is doing work. Hence, the work done for the given process is -3546.55 J