What will be the volume of CO₂ at NTP obtained on heating 10 grams of (90% pure) limestone? (A) 22.4 litre (B) 2.016 litre (C) 2.24 litre (D) 20.16 litre

What will be the volume of CO₂ at NTP obtained on heating 10 grams o

1.	What will be the volume of CO₂ at NTP obtained on heating 10 grams of (90% pure) limestone? (A) 22.4 litre (B) 2.016 litre (C) 2.24 litre (D) 20.16 litre
Answer» udent,◆ Answer -(B) 2.016 litre● Explaination -Mass of pure LIMESTONE is 10×90/100 = 9 g.Moles of limestone = 9/100 = 0.09 molHeating of calcium carbonate gives same no of moles of CO2. HENCE, Moles of CO2 = 0.09 MOL. Volume of CO₂ at NTP is calculated as -Volume = 22.41 × molesVolume = 22.44 × 0.09Volume = 2.016 litreThanks dear. HOPE this helps you...