1.

What will be the van't hoff factor for a solution of K4[FeCN6] if its dissociation is 50%

Answer»

Degree of dissociation, x=50%=0.5
Van't Hoff factor, i= number of moles after dissociation/total number of moles initially

= (1+4x)/1

i=1+4(0.5)=1+2=3



Discussion

No Comment Found

Related InterviewSolutions