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What will be the value of 5 and 15 home equivalent resistance in class cooperatives and parallel cooperatives |
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Answer» Correct option is D R/n 2
As we know R∝l(length of wire) and we are cutting the wire into n equal parts, so each NEW formed wire's resistor ⇒R 1
=R 2
=R 3
=R
=R 5
=...R n
= n R
as the DIAGRAM shows, we are connecting them in parallel series then equivalent resistance of combination is given by R eq
⇒ R eq
1
= R 1
1
+ R 2
1
+ R 3
1
+ R 4
1
+...+ R n
1
⇒ R eq
1
= R n
+ R n
+ R n
+...+ R n
(n times) ⇒ R eq
1
=( R n
)×n ⇒R eq
= n 2
R
correct option will be (D) |
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