1.

what will be the solution of equation sin θ  = 0 ?

Answer»

Given 

 sin θ = 0 

∵ sin θ = sin 0 = sin π = sin 2π = sin (–2π) = .... = 0 

Therefore sin θ = 0 is satisfied by the following values of θ. 

∴ θ = 0, ± π, ± 2π, ± 3π, ± 4π, ..... 

⇒ The general solution of sin θ = 0 is θ = nπ, n∈I



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