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what will be the solution of equation sin θ = 0 ? |
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Answer» Given sin θ = 0 ∵ sin θ = sin 0 = sin π = sin 2π = sin (–2π) = .... = 0 Therefore sin θ = 0 is satisfied by the following values of θ. ∴ θ = 0, ± π, ± 2π, ± 3π, ± 4π, ..... ⇒ The general solution of sin θ = 0 is θ = nπ, n∈I |
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