Saved Bookmarks
| 1. |
What will be the pressure exerted by a mixture of `3.2 g` of methane and `4.4g` of carbon dixide contained in a `9 dm^(3)` flask at `27^(@)C` ? . |
|
Answer» `W_(CH_(4))=3.2 g` Moles of `CH_(4)=3.2/16=0.2` `W_(CO_(2))=4.4 g` Moles of `CO_(2)=4.4/44=0.1` Total moles presnt in mixture `=0.2+0.1=0.3` Volume of flask `=9 dm^(3)=9 L` Temperature `=273+27=300 K` Now for pressure of mixture `=PxxV=nRT` `Pxx9=0.3xx0.821xx300` `P=(0.3xx0.0821xx300)/9=0.821 atm` `=0.821xx1.013xx10^(5) Pa=8.314xx10^(4) Pa` |
|