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What will be the ph value of 0.05 m ba(oh)2 solution? |
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Answer» will be 13. SOLUTION: Ba(OH)2 - Ba2+ 2OH-0.05 M X 2= 0.10M POH= -log(0.10 M) = 1.00pH = 14-pOH= 14 - 1.00=13PLEASE MARK IT AS BRAINLIST |
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