What will be the minimum pressure required to compress 500 dm3 of air

1.	What will be the minimum pressure required to compress 500 dm3 of air at 5 bar to 200 dm3 at 25 °C.
Answer» Given: P₁ = Initial pressure = 5 bar V₁ = Initial volume = 500 dm³ ; V₂ = Final volume = 200 dm³ To find: P₂ = Final pressure Formula: P₁ V₁ = P₂ V₂ (at constant n and T) Calculation: According to Boyle’s law P₁ V₁ = P₂ V₂(at constant n and T) ∴ P₂= \(\frac{P_1V_1}{V_2}\) = \(\frac{5 \times 500}{200}\) = 12.5 bar The minimum pressure required to compress 500 dm³ of air at 5 bar to 200 dm³ at 25 °C is 12.5 bar.

What will be the minimum pressure required to compress 500 dm3 of air at 5 bar to 200 dm3 at 25 °C.

Answer»

Given: P₁ = Initial pressure = 5 bar

V₁ = Initial volume = 500 dm³ ; V₂ = Final volume = 200 dm³

To find: P₂ = Final pressure

Formula: P₁ V₁ = P₂ V₂ (at constant n and T)

Calculation: According to Boyle’s law

P₁ V₁ = P₂ V₂(at constant n and T)

∴ P₂= \(\frac{P_1V_1}{V_2}\) = \(\frac{5 \times 500}{200}\) = 12.5 bar

The minimum pressure required to compress 500 dm³ of air at 5 bar to 200 dm³ at 25 °C is 12.5 bar.