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What will be the freezing point of 0.2 molal aqueous solution of `MgBr_(2)` ? If salt dissociates 40% in solution and `K_(f)` for water is 1.86 KKg `mol^(-1)`A. `-3.35^(@)`CB. `-0.67^(@)`CC. `-0.6^(@)`CD. `-0.45^(@)`C |
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Answer» Correct Answer - B `Delta T_(f)=ixx(1000K_(f)w)/(mW)` `DeltaT^(f)=ixxK_(f)xx"molality` `MgBr_(2)hArrMg^(+2)+2Br^(-)` `i=1-alpha+3alpha` `=1-0.4+3xx0.4=1.8` `:.DeltaT_(f)=1.8xx1.86xx0.2` and `T_(1)T_(f)-DeltaT=-0.67^(@)`C |
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